Objective : Write an algorithm to find two Missing Numbers in a Sequence of Consecutive Numbers
Input: Array, arrA[] with two missing numbers and Range
Output : Two missing numbers
Approach:

 Approach is very simple, Add all the given numbers say S
 Calculate sum of N numbers by formula n(n+1)/2 , say N
 Find sum of two missing numbers a+b = NS
 Now take the product of all given numbers say P
 Now take the product of N numbers , say Np;
 Find the product of two missing numbers ab = NpP
 Now we have a+b and ab , we can easily calculate a and b
Example :
Given array : {10,2,3,5,7,8,9,1}; Range : 10 N (Sum of 1 to 10 ) = 55 S (Sum of given elements ) = 45 a+b = 10(1) Np(Product of 1 to 10) = 3628800 P(Product of given elements) = 151200 So a*b = 24(2) Now we have two equations and two variables, if we solve we will get values 6 and 4.
Complete Code:
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//find the two missing numbers from the sequence of consecutive number  
//Approach is very simple, Add all the given numbers say S  
//Calculate sum of N numbers by formula n(n+1)/2 , say N  
//Find sum of two missing numbers a+b = NS  
//Now take the product of all given numbers say P  
//now take the product of N numbers , say Np;  
//find the product of two missing numbers ab = NpP  
//now we have a+b and ab , we can easily calculate a and b  
public class FindTwoMissingNumbers {  
int Sum;  
int SumN;  
int P=1;  
int Np=1;  
int a,b;  
public int [] missingNumbers(int [] arrA, int range){  
SumN = range*(range+1)/2;  
for(int i=0;i<arrA.length;i++){  
Sum +=arrA[i];  
}  
int s= SumN–Sum;  
for(int i=0;i<arrA.length;i++){  
P *=arrA[i];  
}  
for(int i=1;i<=range;i++){  
Np *=i;  
}  
int product = Np/P;  
// System.out.println(product);  
int diffSqr = (int)Math.sqrt(s*s–4*product); // (ab)^2 = (a+b)^24ab  
a = (s+diffSqr)/2;  
b= s–a;  
int [] result = {a,b};  
return result;  
}  
public static void main(String args[]){  
int [] arrA = {10,2,3,5,7,8,9,1};  
FindTwoMissingNumbers f = new FindTwoMissingNumbers();  
int [] results = f.missingNumbers(arrA, 10);  
System.out.println("Missing numbers are :" + results[0] + " and " + results[1]);  
}  
} 
Output:
Missing numbers are :6 and 4
The example is very good, just a small bug at line 30 in the snippet, it should be (s*2) not (s*s) in the equation
diffSqr = (int)Math.sqrt((s*s)4*product)