**Objective : **Given a 2D matrix of characters. Check whether the word exist in the matrix or not. If it exists then print its path. All movements are allowed (right, left, up, down and diagonally).

**Example**:

**Approach**:

We will show the path as increment counter

- Create a solution matrix of the same structure as Matrix.
- Try each cell a starting point.
- Check current cell is not already used and character in it matches with the character in the word at index (starts will 0).
- Check if index = length of the word, means we have found the word. return true and print the solution matrix.
- If above criteria matches, mark that cell with a number Whenever any cell matches with the criteria, put a number corresponding to it in solution matrix. (start with 0 and keep incrementing it, it will show us the path for the word).
- Now try to solve rest of the problem recursively by making index +1. Check all 8 directions ( up, down, left right, diagonally up-left, diagonally up-right, diagonally down-left, diagonally down-right). Check the boundary conditions as well
- If none of the 8 recursive calls return true, BACKTRACK and undo the changes ( put 0 to corresponding cell in solution matrix) and return false.

- Choose different starting point.
- If all the starting points tried and solution not found, return false
- See the code for better understanding.

**Code**:

Output: 0 0 0 0 0 0 1 0 5 0 0 0 2 4 6 0 0 0 3 7 0 0 0 0 0