Check if the given number is Armstrong number or not

Objective: Given a number, write a program to find out whether the number is Armstrong number or not

What is Armstrong number: Determine the number of digits in the number. Call that n. Then take every digit in the number and raise it to the n power. Add all those together, and if your answer is the original number then it is an Armstrong number.

Example: 

N = 123
digits = 3
13+23+33=36
123 is not Armstrong number.
Output: false N = 153
digits = 3
13+53+33=153
153 is an Armstrong number.
Output: true N = 1634
digits = 4
14+64+34+44=1634
1634 is an Armstrong number.
Output: true N = 2356
digits = 4
24+34+54+64=2018
2018 is not an Armstrong number.
Output: false

Approach:

  • Get all the digits in the number.
  • Let’s say the count of digits is x.
  • Iterate through digits and calculate sum= digit1x +digit2x+…….+digitxx.
  • check if the given number is equal to the sum, means the number is Armstrong, return true else number is not Armstrong, return false. 

Complete Code:

Output:

Number 123 is Armstrong Number: false
Number 153 is Armstrong Number: true
Number 1634 is Armstrong Number: true
Number 2356 is Armstrong Number: false

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If you find anything incorrect or you feel that there is any better approach to solve the above problem, please write comment.
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