Check whether the given number is a perfect square
Objective: Given an integer check whether it is a perfect square.
number = 37 Output: false number = 49 Output: true
This is fun puzzle which is asked in the interview.
- Say number is n.
- Start a loop from 1 to n/2.
- During iteration, for every integer ‘i’, calculate x = i*i.
- Now with this ‘x’ there are 3 possibilities.
- If x == n then n is a perfect square, return true
- If x > n then x has crossed the n, n is not perfect square. Return false
- If above step a or b are not true then continue.
Time Complexity: O(sqrt(n))
37 is square: false 49 is square: true
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If you find anything incorrect or you feel that there is any better approach to solve the above problem, please write comment.