**Objective:** **– **Given a inorder and postorder traversal, write an algorithm to construct a binary tree from that. This problem was asked in the Microsoft coding competition.

**Input:** Inorder and postorder traversals

**Similar Problems: Make a Binary Tree from Given Inorder and Preorder Traveral.**

**Appraoch:**

**int**[] inOrder = { 4, 2, 5, 1, 6, 3, 7 };

**int**[] postOrder = { 4, 5, 2, 6, 7, 3, 1 };.

- Last element in the
*postorder []*will be the*root*of the tree, here it is 1. - Now the search element 1 in
*inorder[]*, say you find it at position*i*, once you find it, make note of elements which are left to*i*(this will construct the leftsubtree) and elements which are right to*i*( this will construct the rightSubtree). - Suppose in previous step, there are X number of elements which are left of ‘
*i’*(which will construct the leftsubtree), take first X elements from the postorder[] traversal, this will be the post order traversal for elements which are left to*i*. similarly if there are Y number of elements which are right of ‘i’ (which will construct the rightsubtree), take next Y elements, after X elements from the postorder[] traversal, this will be the post order traversal for elements which are right to*i* - From previous two steps construct the left and right subtree and link it to root.left and root.right respectively.
- See the picture for better explanation.

**Complete Code:**

**Output**:

inorder traversal of constructed tree : 4 2 5 1 6 3 7

good work!is the worst case complexity O(n^2)?