Interval is defined as [start, end]- the start of the interval to the end of the interval. Given the list of Intervals write an algorithm to find the maximum number of intervals overlapping at any point in time.

**Example:**

Given Intervals: [[0,2], [3,7], [1,5], [7,8], [4,6]] Maximum overlapping: 3 Explanation: Interval (4, 5) is overlapping 3 given intervals [3,7], [1,5], [4,6] Given Intervals: [[0,5], [6,8], [1,7]] Maximum overlapping: 2 Given Intervals: [[0,2], [3,7], [7,8]] Maximum overlapping: 1

**Approach:**

- Create a list and insert all the interval times (both start and end) along with the marker to identify whether the time is start time or end time.
- Sort the list in ascending order of times.
- Initialize
= 0,*counter*= 0.*maxOverlap* - Iterate the list from left to right. For each time-
- If time is start-time – do
.*counter++* - If time is end-time – do
.*counter–* - Check if counter > maxOverlap, do
.*maxOverlap = counter*

- If time is start-time – do
- Return
.*maxOverlap*

**Time Complexity: O(nlogn)**

**Complete Code:**

**Output: **

Given Intervals: [[0,2], [3,7], [1,5], [7,8], [4,6]] Maximum overlapping: 3