Given two arrays where the second array has all the elements from the first array and one extra element.

**Example: **

arrA = [1, 4, 2, 5, 7] arrB = [1, 2, 4, 1, 7, 5] Output: 1 arrA = [1, 8, 2, 0] arrB = [1, 8, 4, 2, 0] Output: 4

**Solution:**

This problem can be solved in many ways, for instance, we can add both the arrays separately and then take a difference between those, this difference will be caused by that extra element in the array.

A better solution would be taking an XOR of both the arrays since we know ** A XOR A = 0** so all the elements which are present in both the arrays will become 0 when taking XOR and the only element will remain, the extra element in one of the arrays. Below is the code for XOR logic

**Code:**

**Output:**

Array A: [3, 4, 5, 2, 9, 6] Array B: [4, 3, 2, 9, 5, 7, 6] Extra Element: 7