Objective: – Given an Integer array. Array contains duplicates of all the numbers in array except one number . Find that number.

Example :

int [] A = { 2,1,3,5,5,3,2,1,6,7,7,8,8};
Output : Missing duplicate is 6
Appraoch:

Naive solution is use Hash Table ..space complexity – O(n)
Better solution – XOR
A^A = 0 and A^B^A = B, so if we XOR all the elements, answer will be the missing no
If we have only one element, the missing no will be that no
Code: Run This Code

Output :

Missing duplicate is 6
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If you find anything incorrect or you feel that there is any better approach to solve the above problem, please write comment.
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