Given an array arrA[], find the maximum j – i such that arr[j] > arr[i].

Objective: Given an array arrA[], find the maximum j – i such that arr[j] > arr[i].
Example:

int[] arrA = { 12, 3, 1, 5, 6, 4, 10, 9, 8, 0 };
Output: Max(j-i) where j>i and A[j]>A[i] is : 7

Approach:

  • Create 2 Auxilary Arrays say Lmin[] and Rmax[] of the same size as main array
  • Put Lmin[0]=0 and Rmax[Rmax.length-1] =Rmax.length-1
  • Traverse the main array and fill the Lmin array with the index position which has the minimum value so far
  • Traverse the main array backwords and fill the Rmax array with the index position which has the maximun value so far
  • Initialize distance_so_far = 0
  • Navigate through the main array and if (Lmin[i]<Rmax[i])
  • Then check if (Rmax[i]-Lmin[i])>distance_so_far then distance_so_far = Rmax[i]-Lmin[i]
  • Return distance_so_far

Complete Code:


Output:

Max(j-i) where j>i and A[j]>A[i] is : 7

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If you find anything incorrect or you feel that there is any better approach to solve the above problem, please write comment.
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