# Make a Binary Tree from Given Inorder and Preorder Traveral.

**Objective:** **– **Given a inorder and preorder traversal, construct a binary tree from that.

**Input:** Inorder and preorder traversals

**Similar Problem: Construct a binary tree from given Inorder and Postorder Traversal**

**Approach:**

**int** [] inOrder = {2,5,6,10,12,14,15};

**int** [] preOrder = {10,5,2,6,14,12,15};

- First element in
*preorder[]*will be the*root*of the tree, here its 10. - Now the search element 10 in
*inorder[]*, say you find it at position*i*, once you find it, make note of elements which are left to*i*(this will construct the leftsubtree) and elements which are right to*i*( this will construct the rightSubtree). - See this step above and recursively construct left subtree and link it root.left and recursively construct right subtree and link it root.right.

- See the picture and code.

**Complete Code:**

**Output**:

Constructed Tree : 2 5 6 10 12 14 15

Broken method.

No solution for —

ADFGHKLPQRWZ(preorder)

GFHKDLAWRQPZ(inorder)

GKHFLDWRQZPA (Postorder)