Objective: – Given a binary tree and X, write an algorithm to Print all the paths starting from root so that sum of all the nodes in path equals to a given number.
Example:
Approach:
- Create a global variable as String = path.
- Do the preorder
- if root is greater than Sum required, return.
- If not then, add root to the path and update the required sum (sum=sum-root.data).
- if sum required =0, means we have found the path, print it.
- See the code for better understanding.
Code:
Output:
1 2 7 1 3 6
By doing the preorder traversal, on the left branch all of the 1, 2, 7 and 5 nodes will be added; is that a valid scenario? Since I’m asking I guess that is not a valid path.
The solution also does not catch the scenario where sum = 12. In that context, the path would consist only of nodes 2, 1, 3 and 6. I’d guess that is a valid path in the tree, right?
Thanks Eugen. It was a solution for some other problem. I have updated the post. Do let me know if you find issues in other posts.