Print the Binary Tree in Vertical Order Path.

Objective: Given a binary tree, print it in vertical order path.

What is Vertical Order

Vertical Order Print Exampleas you can see in the example above, [4],[2], [1,5,6],[3],[7] are the verical order of the given binary tree.


  • Its a tricky solution.
  • Do the preordertraversal.
  • Take a variable called level, when ever you go left, do level++ AND when ever you go right do level–.
  • With step above we have separated out the levels vertically.
  • Now you need to store the elements of each level, so create a TreeMap and the (key,value) pair will be (level,elements at that level).
  • At the end iterate through the TreeMap and print the results.
Separate out the vertical levels
Separate out the vertical levels

Complete Code:

import java.util.ArrayList;
import java.util.Set;
import java.util.TreeMap;
public class VerticalOrder {
public static TreeMap<Integer, ArrayList> ht = new TreeMap<>();
public ArrayList<Integer> al;
public void vertical(Node root, int level) {
if (root == null) {
if (ht.containsKey(level)) {
ArrayList x = ht.get(level);
ht.put(level, x);
} else {
al = new ArrayList<>();
ht.put(level, al);
vertical(root.left, level1);
vertical(root.right, level+1);
public void printResult(TreeMap ht) {
Set<Integer> i = ht.keySet();
for (int keys : i) {
public static void main(String args[]) {
Node root = new Node(1);
root.left = new Node(2);
root.right = new Node(3);
root.left.left = new Node(4);
root.left.right = new Node(5);
root.right.left = new Node(6);
root.right.right = new Node(7);
VerticalOrder p = new VerticalOrder();
p.vertical(root, 0);
class Node {
int data;
Node left;
Node right;
public Node(int data) { = data;
left = null;
right = null;

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