**Objective:** Given a linked list, swap every kth node in that. If at the end of the list remaining nodes are less than k, leave them untouched.

**Input:** A linked list, A number k.

**Example:**

Input : ->1->2->3->4->5->6->7->8->9->10 , K = 4
Output: ->4->2->3->1->8->6->7->5->9->10

**Approach**:

- Take 3 Pointers, ptrOne, ptrTwo and ptrTwo_prev.
- ptrOne and ptrTwo_prev points at head node.
- ptrTwo points at next node of ptrTwo_prev.
- Move the ptrTwo and ptrTwo_prev k-2 times, since we need one pointer each at both ends for swapping so move pointers only k-2 times.
- Create another pointer , NewHead and point it to ptrTwo.next.
- Now we have ptrOne at head and ptrTwo at kth position, swap them with the help of ptrTwo_prev.
- This function will returns the head.
- Now make a recursive call with newHead.

**ptrOne.next = reverseNodes(newHead, k); **

Swap Evey Kth Node in a linked list

**Complete Code:**

**Output:**
Original Link List 1 : ->1->2->3->4->5->6->7->8->9->10
Swap Every 4th Node :
->4->2->3->1->8->6->7->5->9->10

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If you find anything incorrect or you feel that there is any better approach to solve the above problem, please write comment.

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