Tagged: Expert

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Articulation Points OR Cut Vertices in a Graph

Objective: Given a graph, write an algorithm to find all the articulation points or cut vertices. Articulation Points: In a graph, a vertex is called an articulation point if removal of that vertex (along...

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Find the number of distinct Islands OR connected components.

Objective: Given a 2d grid map of ‘1’s (land) and ‘0’s (water), count the number of distinct or unique islands. Island: An island is surrounded by water and is formed by connecting adjacent lands...

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Print All Paths in Dijkstra’s Shortest Path Algorithm

Objective:  Given a graph and a source vertex write an algorithm to find the shortest path from the source vertex to all the vertices and print the paths all well. Example: We strongly recommend reading...

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Check if Graph is Bipartite – Adjacency List using Depth-First Search(DFS)

Objective: Given a graph represented by the adjacency List, write a Depth-First Search(DFS) algorithm to check whether the graph is bipartite or not. Earlier we have solved the same problem using Adjacency Matrix (Check...

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Social Network Problem

Given: There are N people in a social network and there are friends group. Each person can be part of a friend group of a specific size. Number of people in the social network...

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Reverse a Stack using recursion – In Place (Without using extra memory)

Objective: Given a Stack, write an algorithm to reverse the stack. Example: Original Stack: [14, 9, 67, 91, 101, 25] Reversed Stack: [25, 101, 91, 67, 9, 14] Approach: Use Recursion In this solution,...

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K-Means Algorithm

The algorithm of kMeans is an unsupervised learning algorithm for clustering a set of items into groups. Given a set of multi-dimensional items and a number of clusters, k, we are tasked of categorizing...

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Max Flow Problem – Ford-Fulkerson Algorithm

Objective: Given a directed graph that represents a flow network involving source(S) vertex and Sink (T) vertex.  Each edge in the graph has an individual capacity which is the maximum flow that edge allows....

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